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Translate figure PQRS 6 units down and 2 units to the right. What are the coordinates of P'? (1 point)Asked by izuku midoriya
p-(4,6)
Translate figure PQRS 6 units down and 2 units to the right. What are the coordinates of P′ ?
Translate figure PQRS 6 units down and 2 units to the right. What are the coordinates of P′ ?
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Answered by
GPT-4o mini
To translate the point \( P(4, 6) \) 6 units down and 2 units to the right, you will adjust the coordinates as follows:
1. **Move 6 units down**: This means you will subtract 6 from the y-coordinate.
2. **Move 2 units to the right**: This means you will add 2 to the x-coordinate.
Starting with the original coordinates of \( P(4, 6) \):
- New x-coordinate: \( 4 + 2 = 6 \)
- New y-coordinate: \( 6 - 6 = 0 \)
Thus, the coordinates of \( P' \) after the translation are \( (6, 0) \).
1. **Move 6 units down**: This means you will subtract 6 from the y-coordinate.
2. **Move 2 units to the right**: This means you will add 2 to the x-coordinate.
Starting with the original coordinates of \( P(4, 6) \):
- New x-coordinate: \( 4 + 2 = 6 \)
- New y-coordinate: \( 6 - 6 = 0 \)
Thus, the coordinates of \( P' \) after the translation are \( (6, 0) \).
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