Question

Translate figure PQRS 6 units down and 2 units to the right. What are the coordinates of P′
P'?

P = (4, 6)
S = (2, 2)
Q = (7, 2)
R = (5, -2)

Answer 1

To translate the point \( P \) with coordinates \( P = (4, 6) \) 6 units down and 2 units to the right, we will follow these steps:

1. **Translate 6 units down**: This means we subtract 6 from the y-coordinate.
\[
y' = 6 - 6 = 0
\]

2. **Translate 2 units to the right**: This means we add 2 to the x-coordinate.
\[
x' = 4 + 2 = 6
\]

Putting these two translations together, the new coordinates for \( P' \) are:
\[
P' = (x', y') = (6, 0)
\]

Thus, the coordinates of \( P' \) are \( (6, 0) \).