Asked by Michelle
                Please me find the points to graph for the follow equations.
x+3y<9, 3x+y<9, x>0, Y>0
            
        x+3y<9, 3x+y<9, x>0, Y>0
Answers
                    Answered by
            Henry
            
    Since your inequalities do not have
an equal sign, the points on the
boundry line should not satisfy the
inequalities. All of your boundry lines
should be dotted lines.
X + 3Y < 9. Graph: X + 3Y = 9:
(0 , 3) , (3 , 2) , (9 , 0). If you
use only 2 points, use the end points.
All points below this line should
satisfy the ineq.
3X + Y < 9. Graph: 3X + Y = 9,
(0 , 9),(2 , 3), (3 , 0). If you use
only 2 of these points, use the end
points. All points below this line
should satisfy the ineq.
X < 0. Graph: X = 0:
(0 , 2) , (0 , 4) , (0 , 6). This
is a vertical line that lies on the
Y- axis. All points to the rt. should
satisfy this Ineq.
Y > 0. Graph: Y = 0.
(2 , 0 ) , (4 , 0) , (6 , 0).This is
a hor. line that lies on the X-axis.
All points above this line should
satisfy the Ineq.
    
an equal sign, the points on the
boundry line should not satisfy the
inequalities. All of your boundry lines
should be dotted lines.
X + 3Y < 9. Graph: X + 3Y = 9:
(0 , 3) , (3 , 2) , (9 , 0). If you
use only 2 points, use the end points.
All points below this line should
satisfy the ineq.
3X + Y < 9. Graph: 3X + Y = 9,
(0 , 9),(2 , 3), (3 , 0). If you use
only 2 of these points, use the end
points. All points below this line
should satisfy the ineq.
X < 0. Graph: X = 0:
(0 , 2) , (0 , 4) , (0 , 6). This
is a vertical line that lies on the
Y- axis. All points to the rt. should
satisfy this Ineq.
Y > 0. Graph: Y = 0.
(2 , 0 ) , (4 , 0) , (6 , 0).This is
a hor. line that lies on the X-axis.
All points above this line should
satisfy the Ineq.
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