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Question

Function 1: f(x)=4x+2

Function 2:

Compare the two functions and identify the y-values of the y-intercepts. Which function has the smaller value?

(1 point)
Responses

Function 1: (0,2); Function 2: (0,−2). Function 2 has the smaller value.

Function 1: (−2,0); Function 2: (2,0). Function 1 has the smaller value.

Function 1: (0,−2); Function 2: (0,2). Function 2 has the smaller value.

Function 1: (-1, 0); Function 2: (-1, 0). they have identical values.

Answer 1

To find the y-intercepts of the functions, we need to evaluate each function at \( x = 0 \).

For Function 1: \[ f(x) = 4x + 2 \] Substituting \( x = 0 \): \[ f(0) = 4(0) + 2 = 2 \] So the y-intercept for Function 1 is (0, 2).

For Function 2, since the equation is not provided, we cannot calculate its y-intercept directly. However, from the responses given, we see that Function 2's y-intercept must correspond to one of the values provided.

Looking at the provided choices:

• Function 1: (0, 2); Function 2: (0, −2). Function 2 has the smaller value.

Since we see that Function 2 has a y-intercept of (0, -2), while Function 1 has a y-intercept of (0, 2), it confirms that Function 1 has a y-value of 2 and Function 2 has a y-value of -2.

Thus, Function 2 has the smaller value.

The correct response is: Function 1: (0,2); Function 2: (0,−2). Function 2 has the smaller value.