Asked by anonymous
A coast guard patrol boat is 14.8 km east of the Brier Island Lighthouse. A disabled yacht is 7.5km south of the lighthouse.
a) How far is the patrol boat from the yacht, to the nearest tenth of a kilometer?
b) At what angle south of due west, to the nearest degree, should the patrol boat travel to reach the yacht?
a) How far is the patrol boat from the yacht, to the nearest tenth of a kilometer?
b) At what angle south of due west, to the nearest degree, should the patrol boat travel to reach the yacht?
Answers
Answered by
Henry
a. d^2 = (14.8)^2 + (7.5)^2 = 275.19
d = sqrt(275.19) = 16.6 km.
b. Tan B = 7.5/14.8 = 0.5068, B = 26.9
deg.
d = sqrt(275.19) = 16.6 km.
b. Tan B = 7.5/14.8 = 0.5068, B = 26.9
deg.
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