record the initial number of gallons of water in the pool.

Question

t
g
0
1
2
3
4
5
6
7
8
9
10
0
250
500
750
1,000
1,250
1,500
1,750
2,000
2,250
2,500
Time in hours
Gallons of water in the pool
Rate of change: 500
Initial amount: 250

Gallons of water in the pool = Initial number of gallons of water + Change in gallons
of water
g =

Answer 1

To express the relationship between the number of gallons of water in the pool (\(g\)), the initial number of gallons of water, and the change in gallons of water with respect to time, we can use the following formula:

\[ g = \text{Initial amount} + \text{Rate of change} \times t \]

From your provided information, we have the following:

• Initial amount = 250 gallons
• Rate of change = 500 gallons per hour
• \(t\) = time in hours

Therefore, the equation becomes:

\[ g = 250 + 500t \]

This means that the number of gallons of water in the pool increases by 500 gallons for every hour that passes, starting from an initial amount of 250 gallons.