Asked by tee
hw do l wrk ths out: A record has a diameter of 30cm and rotates at 33 n 1/3 revolution per minute. Hw far does a point on the edge of the record travel in a minute? (use the 3,4 for pie n gve answer in metres
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The radius of the disc is half of the diameter, which is 15 cm or 0.15 m.
The circumference of the disc is C = πd = 3.14 x 0.3 m = 0.942 m.
The distance traveled by a point on the edge of the disc in one revolution is equal to the circumference of the disc, which is 0.942 m.
In one minute, the disc makes 33 1/3 revolutions, so the distance traveled by a point on the edge of the disc in one minute is:
distance = 0.942 m/rev x 33.33 rev/min = 31.4 m/min
Therefore, a point on the edge of the disc travels 31.4 meters in one minute.
The circumference of the disc is C = πd = 3.14 x 0.3 m = 0.942 m.
The distance traveled by a point on the edge of the disc in one revolution is equal to the circumference of the disc, which is 0.942 m.
In one minute, the disc makes 33 1/3 revolutions, so the distance traveled by a point on the edge of the disc in one minute is:
distance = 0.942 m/rev x 33.33 rev/min = 31.4 m/min
Therefore, a point on the edge of the disc travels 31.4 meters in one minute.
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