Ask a New Question

Asked by Anonymous

An electron orbits a proton at a radius of 5.38 10-11 m. What is the magnitude of the magnetic field at the proton due to the orbital motion of the electron?
15 years ago

Answers

Answered by bobpursley
Oliver Heaviside, in 1888, first solved this question for moving charges.

B=mu*q/4PI * v/r^2

http://bama.ua.edu/~stjones/puzzles.htm
15 years ago

Related Questions

An electron and a proton are each placed at rest in an external uniform electric field of magnitude... An electron and a proton are separated by 2.0 nm. (a) What is the magnitude of the force on the elec... A proton orbits a negatively charged wire that has a linear charge density of 8.0 x 10 -9 C/m. What... An electron orbits a 3.0 cm diameter metal ball 5.0 mm above the surface. The orbital period of the... if a proton and an electron are released when they 2.0 x 10^-10 m apart, find the initial accelerati... A single electron orbits a lithium nucleus that contains three protons (+3e). The radius of the orbi... An electron and a proton have charges of opposite sign, but the magnitude of their charges has the s... An electron and a proton are 1.0x10^-10 m apart. in the absence of any other charges, what is the el... An electron and a proton have charges of equal magnitude but of opposite sign. The magnitude of the... Is it a proton and electron or a proton and neutron that’s found in the nucleus of an atom?
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use