Question

A gallon of water weighs about 8.3 lb. An Olympic-sized swimming pool holds 6.6×105
gallons. What is the approximate weight of the water in an Olympic-sized swimming pool? Write the answer in scientific notation.(1 point)
Responses

5.478×106
lb.
5.478 times 10 superscript 6 baseline lb.

54.78×105
lb.
54.78 times 10 superscript 5 baseline lb.

5.478×105
lb.
5.478 times 10 superscript 5 baseline lb.

54.78×106
lb.

Answer 1

To find the weight of the water in an Olympic-sized swimming pool, we can start with the given values:

- Weight of water per gallon: 8.3 lb
- Volume of the swimming pool: \(6.6 \times 10^5\) gallons

Now, we can calculate the total weight of the water in the pool by multiplying the weight per gallon by the total number of gallons:

\[
\text{Total weight} = \text{Weight per gallon} \times \text{Volume of the pool}
\]

\[
\text{Total weight} = 8.3 \, \text{lb/gallon} \times 6.6 \times 10^5 \, \text{gallons}
\]

Calculating the multiplication:

\[
8.3 \times 6.6 = 54.78
\]

Now multiply by \(10^5\):

\[
\text{Total weight} = 54.78 \times 10^5 \, \text{lb}
\]

To express this in proper scientific notation, we adjust it to have a single non-zero digit to the left of the decimal:

\[
54.78 \times 10^5 = 5.478 \times 10^6 \, \text{lb}
\]

Thus, the approximate weight of the water in an Olympic-sized swimming pool is:

\[
\boxed{5.478 \times 10^6 \, \text{lb}}
\]