Question

A gallon of water weighs about 8.3 lb. An Olympic-sized swimming pool holds 6.6 × 105
gallons. What is the approximate weight of the water in an Olympic-sized swimming pool?(1 point)
Responses

Answer 1

To find the approximate weight of the water in an Olympic-sized swimming pool, we can multiply the number of gallons the pool holds by the weight of a gallon of water.

Given:
- Weight of a gallon of water = 8.3 lb
- Volume of an Olympic-sized swimming pool = 6.6 × 10^5 gallons

Now, we can calculate the total weight:

\[
\text{Total weight} = \text{Volume of pool} \times \text{Weight per gallon}
\]
\[
\text{Total weight} = 6.6 \times 10^5 \text{ gallons} \times 8.3 \text{ lb/gallon}
\]

Now performing the multiplication:

\[
6.6 \times 8.3 = 54.78
\]
\[
\text{Total weight} = 54.78 \times 10^5 \text{ lb} = 5.478 \times 10^6 \text{ lb}
\]

Therefore, the approximate weight of the water in an Olympic-sized swimming pool is:

**5.48 million pounds (or about 5.5 million pounds)**.