Question

A carry suitcase is 9.5 inches long 16 inches wide and 22.5 inches height what is the surface area

Answer 1

To calculate the surface area \( S \) of a rectangular suitcase, you can use the formula:

\[
S = 2lw + 2lh + 2wh
\]

where:
- \( l \) is the length,
- \( w \) is the width,
- \( h \) is the height.

Given the dimensions:
- \( l = 9.5 \, \text{inches} \)
- \( w = 16 \, \text{inches} \)
- \( h = 22.5 \, \text{inches} \)

Let's calculate it step by step:

1. Calculate \( lw \):
\[
lw = 9.5 \times 16 = 152 \, \text{square inches}
\]

2. Calculate \( lh \):
\[
lh = 9.5 \times 22.5 = 213.75 \, \text{square inches}
\]

3. Calculate \( wh \):
\[
wh = 16 \times 22.5 = 360 \, \text{square inches}
\]

Now combine these results into the surface area formula:

\[
S = 2(152) + 2(213.75) + 2(360)
\]

\[
S = 304 + 427.5 + 720
\]

\[
S = 1451.5 \, \text{square inches}
\]

Therefore, the surface area of the suitcase is \( 1451.5 \, \text{square inches} \).