A carry-on suitcase is 9.5 inches long, 16 inches wide, and 22.5 inches high. What is the surface area of the suitcase?

96 in.2
2
96 in.2

1,451.5 in.2
2
1,451.5 in.2

3,420 in.2
2
3,420 in.2

725.75 in.2

1 answer

To find the surface area of the suitcase, we can use the formula for the surface area of a rectangular prism:

\[ \text{Surface Area} = 2(lw + lh + wh) \]

where:

  • \( l \) is the length,
  • \( w \) is the width,
  • \( h \) is the height.

Given:

  • \( l = 9.5 \) inches,
  • \( w = 16 \) inches,
  • \( h = 22.5 \) inches.

Now, substitute the values into the formula:

  1. Calculate \( lw \): \[ lw = 9.5 \times 16 = 152 \text{ in}^2 \]

  2. Calculate \( lh \): \[ lh = 9.5 \times 22.5 = 213.75 \text{ in}^2 \]

  3. Calculate \( wh \): \[ wh = 16 \times 22.5 = 360 \text{ in}^2 \]

Now add these areas together: \[ lw + lh + wh = 152 + 213.75 + 360 = 725.75 \text{ in}^2 \]

Finally, multiply by 2 to find the total surface area: \[ \text{Surface Area} = 2 \times 725.75 = 1451.5 \text{ in}^2 \]

Therefore, the surface area of the suitcase is 1,451.5 inĀ².