To complete the table for the function \( f(x) = |2x + 1| + 1 \), we need to evaluate \( f(x) \) at the given values of \( x \).
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For \( x = -3 \): \[ f(-3) = |2(-3) + 1| + 1 = |-6 + 1| + 1 = |-5| + 1 = 5 + 1 = 6 \]
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For \( x = -1 \): \[ f(-1) = |2(-1) + 1| + 1 = |-2 + 1| + 1 = |-1| + 1 = 1 + 1 = 2 \]
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For \( x = 1 \): \[ f(1) = |2(1) + 1| + 1 = |2 + 1| + 1 = |3| + 1 = 3 + 1 = 4 \]
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For \( x = 3 \): \[ f(3) = |2(3) + 1| + 1 = |6 + 1| + 1 = |7| + 1 = 7 + 1 = 8 \]
Now, we can complete the table:
\[ \begin{array}{|c|c|} \hline x & f(x) \ \hline -3 & 6 \ -1 & 2 \ 1 & 4 \ 3 & 8 \ \hline \end{array} \]