Question

1. Use the table to complete the statement.

x Substituted Evaluate True Statement?
−3/4

−1/2

1/2



(1 point)
For the quadratic equation −2x2−3x+2=0
, complete the table by testing each of the given values to determine whether it is a solution. Identify which one of the values is in the solution set. Only x =

is in the solution set.

Answer 1

To determine which values satisfy the quadratic equation \(-2x^2 - 3x + 2 = 0\), we will substitute each value of \(x\) into the equation and evaluate.

### Substituting Each Value:

1. For \(x = -\frac{3}{4}\):
\[
-2\left(-\frac{3}{4}\right)^2 - 3\left(-\frac{3}{4}\right) + 2 = -2\left(\frac{9}{16}\right) + \frac{9}{4} + 2
\]
\[
= -\frac{18}{16} + \frac{9}{4} + 2 = -\frac{9}{8} + \frac{9}{4} + 2
\]
\[
= -\frac{9}{8} + \frac{18}{8} + \frac{16}{8} = -\frac{9}{8} + \frac{34}{8} = \frac{25}{8} \neq 0
\]

2. For \(x = -\frac{1}{2}\):
\[
-2\left(-\frac{1}{2}\right)^2 - 3\left(-\frac{1}{2}\right) + 2 = -2\left(\frac{1}{4}\right) + \frac{3}{2} + 2
\]
\[
= -\frac{1}{2} + \frac{3}{2} + 2 = \frac{2}{2} + 2 = 1 + 2 = 3 \neq 0
\]

3. For \(x = \frac{1}{2}\):
\[
-2\left(\frac{1}{2}\right)^2 - 3\left(\frac{1}{2}\right) + 2 = -2\left(\frac{1}{4}\right) - \frac{3}{2} + 2
\]
\[
= -\frac{1}{2} - \frac{3}{2} + 2 = -2 + 2 = 0
\]

### Table Completion:

| x | Substituted | Evaluate | True Statement? |
|----------|-------------|---------------------|------------------------|
| -3/4 | \(-2(-\frac{3}{4})^2 - 3(-\frac{3}{4}) + 2\) | \(\frac{25}{8}\) | False |
| -1/2 | \(-2(-\frac{1}{2})^2 - 3(-\frac{1}{2}) + 2\) | \(3\) | False |
| 1/2 | \(-2(\frac{1}{2})^2 - 3(\frac{1}{2}) + 2\) | \(0\) | True |

### Conclusion:
Only \(x = \frac{1}{2}\) is in the solution set.