Asked by evergreen
Complete the table.
f(x) = |–4x − 1|
x f(x)
–1
0
1
2
f(x) = |–4x − 1|
x f(x)
–1
0
1
2
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To complete the table, we need to evaluate the function \( f(x) = |–4x – 1| \) at the given values of \( x \).
1. For \( x = -1 \):
\[
f(-1) = |–4(-1) – 1| = |4 – 1| = |3| = 3
\]
2. For \( x = 0 \):
\[
f(0) = |–4(0) – 1| = |0 – 1| = |-1| = 1
\]
3. For \( x = 1 \):
\[
f(1) = |–4(1) – 1| = |-4 – 1| = |-5| = 5
\]
4. For \( x = 2 \):
\[
f(2) = |–4(2) – 1| = |-8 – 1| = |-9| = 9
\]
Now, we can fill in the table:
\[
\begin{array}{|c|c|}
\hline
x & f(x) \\
\hline
-1 & 3 \\
0 & 1 \\
1 & 5 \\
2 & 9 \\
\hline
\end{array}
\]
1. For \( x = -1 \):
\[
f(-1) = |–4(-1) – 1| = |4 – 1| = |3| = 3
\]
2. For \( x = 0 \):
\[
f(0) = |–4(0) – 1| = |0 – 1| = |-1| = 1
\]
3. For \( x = 1 \):
\[
f(1) = |–4(1) – 1| = |-4 – 1| = |-5| = 5
\]
4. For \( x = 2 \):
\[
f(2) = |–4(2) – 1| = |-8 – 1| = |-9| = 9
\]
Now, we can fill in the table:
\[
\begin{array}{|c|c|}
\hline
x & f(x) \\
\hline
-1 & 3 \\
0 & 1 \\
1 & 5 \\
2 & 9 \\
\hline
\end{array}
\]
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