To complete the table, we need to evaluate the function \( f(x) = |–4x – 1| \) at the given values of \( x \).
-
For \( x = -1 \): \[ f(-1) = |–4(-1) – 1| = |4 – 1| = |3| = 3 \]
-
For \( x = 0 \): \[ f(0) = |–4(0) – 1| = |0 – 1| = |-1| = 1 \]
-
For \( x = 1 \): \[ f(1) = |–4(1) – 1| = |-4 – 1| = |-5| = 5 \]
-
For \( x = 2 \): \[ f(2) = |–4(2) – 1| = |-8 – 1| = |-9| = 9 \]
Now, we can fill in the table:
\[ \begin{array}{|c|c|} \hline x & f(x) \ \hline -1 & 3 \ 0 & 1 \ 1 & 5 \ 2 & 9 \ \hline \end{array} \]