Complete the table.

Question

f(x) = –2x2 + 8
x f(x)
–1
0
1
2

Answer 1

To complete the table for the function \( f(x) = -2x^2 + 8 \), we will calculate \( f(x) \) for each value of \( x \).

1. For \( x = -1 \): \[ f(-1) = -2(-1)^2 + 8 = -2(1) + 8 = -2 + 8 = 6 \]

2. For \( x = 0 \): \[ f(0) = -2(0)^2 + 8 = -2(0) + 8 = 0 + 8 = 8 \]

3. For \( x = 1 \): \[ f(1) = -2(1)^2 + 8 = -2(1) + 8 = -2 + 8 = 6 \]

4. For \( x = 2 \): \[ f(2) = -2(2)^2 + 8 = -2(4) + 8 = -8 + 8 = 0 \]

Now, we can fill in the table:

\[ \begin{array}{|c|c|} \hline x & f(x) \ \hline -1 & 6 \ 0 & 8 \ 1 & 6 \ 2 & 0 \ \hline \end{array} \]

So the completed table is:

\[ \begin{array}{|c|c|} \hline x & f(x) \ \hline -1 & 6 \ 0 & 8 \ 1 & 6 \ 2 & 0 \ \hline \end{array} \]