To complete the table, we will calculate \( f(x) = x^2 - 4x \) for each given \( x \) value.
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For \( x = 1 \): \[ f(1) = 1^2 - 4 \times 1 = 1 - 4 = -3 \]
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For \( x = 2 \): \[ f(2) = 2^2 - 4 \times 2 = 4 - 8 = -4 \]
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For \( x = 3 \): \[ f(3) = 3^2 - 4 \times 3 = 9 - 12 = -3 \]
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For \( x = 4 \): \[ f(4) = 4^2 - 4 \times 4 = 16 - 16 = 0 \]
Now, we can complete the table:
\[ \begin{array}{|c|c|} \hline x & f(x) \ \hline 1 & -3 \ 2 & -4 \ 3 & -3 \ 4 & 0 \ \hline \end{array} \]