Asked by evergreen
                Complete the table.
f(x) = –2x + 3
x
f(x)
0
3
1
2
3
            
        f(x) = –2x + 3
x
f(x)
0
3
1
2
3
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT-4o mini
            
    To complete the table using the function \( f(x) = -2x + 3 \), we can calculate \( f(x) \) for each given \( x \) value.
Here's the table calculation step by step:
1. **For \( x = 0 \)**:
\[
f(0) = -2(0) + 3 = 3
\]
2. **For \( x = 1 \)**:
\[
f(1) = -2(1) + 3 = -2 + 3 = 1
\]
3. **For \( x = 2 \)**:
\[
f(2) = -2(2) + 3 = -4 + 3 = -1
\]
4. **For \( x = 3 \)**:
\[
f(3) = -2(3) + 3 = -6 + 3 = -3
\]
Now we can fill in the table:
\[
\begin{array}{|c|c|}
\hline
x & f(x) \\
\hline
0 & 3 \\
1 & 1 \\
2 & -1 \\
3 & -3 \\
\hline
\end{array}
\]
So your completed table is:
\[
\begin{array}{|c|c|}
\hline
x & f(x) \\
\hline
0 & 3 \\
1 & 1 \\
2 & -1 \\
3 & -3 \\
\hline
\end{array}
\]
    
Here's the table calculation step by step:
1. **For \( x = 0 \)**:
\[
f(0) = -2(0) + 3 = 3
\]
2. **For \( x = 1 \)**:
\[
f(1) = -2(1) + 3 = -2 + 3 = 1
\]
3. **For \( x = 2 \)**:
\[
f(2) = -2(2) + 3 = -4 + 3 = -1
\]
4. **For \( x = 3 \)**:
\[
f(3) = -2(3) + 3 = -6 + 3 = -3
\]
Now we can fill in the table:
\[
\begin{array}{|c|c|}
\hline
x & f(x) \\
\hline
0 & 3 \\
1 & 1 \\
2 & -1 \\
3 & -3 \\
\hline
\end{array}
\]
So your completed table is:
\[
\begin{array}{|c|c|}
\hline
x & f(x) \\
\hline
0 & 3 \\
1 & 1 \\
2 & -1 \\
3 & -3 \\
\hline
\end{array}
\]
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