To complete the table using the function \( f(x) = x + 1 \), we will substitute the values of \( x \) into the function.
Here’s the table filled out:
| x | f(x) | |---|--------| | 2 | 3 | | 4 | 5 | | 6 | 7 | | 8 | 9 |
So, for each \( x \):
- When \( x = 2 \), \( f(2) = 2 + 1 = 3 \)
- When \( x = 4 \), \( f(4) = 4 + 1 = 5 \)
- When \( x = 6 \), \( f(6) = 6 + 1 = 7 \)
- When \( x = 8 \), \( f(8) = 8 + 1 = 9 \)