The picture shows a container that Rene uses to freeze water:

A cylinder is shown with a base diameter of 6 centimeters and a height of 8 centimeters.

What is the minimum number of identical containers Rene would need to make 2,000 cm3 of ice? (Use π = 3.14.) (1 point)

27

9

3

2

1 answer

To find the minimum number of identical containers Rene would need to make 2,000 cm³ of ice, we first need to calculate the volume of one container, which is in the shape of a cylinder.

The formula for the volume \( V \) of a cylinder is given by:

\[ V = \pi r^2 h \]

Where:

  • \( r \) is the radius of the base.
  • \( h \) is the height of the cylinder.
  1. Calculate the radius: The diameter of the base is 6 cm, so the radius \( r \) is:

\[ r = \frac{6 \text{ cm}}{2} = 3 \text{ cm} \]

  1. Substitute values into the volume formula: The height \( h \) is 8 cm. Now plug in the values into the formula using \( \pi = 3.14 \):

\[ V = 3.14 \times (3 \text{ cm})^2 \times 8 \text{ cm} \]

  1. Calculate the squared radius:

\[ (3 \text{ cm})^2 = 9 \text{ cm}^2 \]

  1. Calculate the volume:

\[ V = 3.14 \times 9 \text{ cm}^2 \times 8 \text{ cm} = 3.14 \times 72 \text{ cm}^3 = 226.08 \text{ cm}^3 \]

  1. Find the number of containers needed:

To find how many containers are needed to make 2,000 cm³ of ice, we divide the total volume needed by the volume of one container:

\[ \text{Number of containers} = \frac{2000 \text{ cm}^3}{226.08 \text{ cm}^3} \]

Calculating this gives:

\[ \text{Number of containers} \approx 8.84 \]

Since we can't have a fraction of a container, we round up to the nearest whole number:

\[ \text{Number of containers} = 9 \]

Thus, the minimum number of identical containers Rene would need to make 2,000 cm³ of ice is 9.

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