Asked by Celina

The device shown below contains 2 kg of water. When the cylinder is allowed to fall 250 m, the temperature of the water increases by 1.4°C. Suppose 2 kg of water are added to the container and the cylinder is allowed to fall 750 m. What would the increase in temperature be in this case?
Answered by scott
work (energy) is proportional to the height

doubling the amount of water will halve the temperature change

Δt = 1.4ºC * (750 m / 250 m) * [2 kg / (2 kg + 2 kg)]
Answered by Celina
The device shown below contains 2 kg of water. The cylinder is allowed to fall 800 m during which the temperature of the water increases by 2.4°C. Some amount of water is added to the container and the experiment is repeated. All other values remain constant. This time the temperature of the water increases by 1.2°C. How much water was added to the container?
Answered by scott
same height ... half the temp. increase ... must be twice the amount of water
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