Since triangle CDE is similar to triangle PQR (indicated by the notation triangleCDE ~ trianglePQR), the corresponding angles are equal.
We know the measures of angles C and D:
- \( m\angle C = 20^\circ \)
- \( m\angle D = 60^\circ \)
To find the measure of angle E in triangle CDE, we use the fact that the sum of the angles in any triangle is \(180^\circ\): \[ m\angle E = 180^\circ - m\angle C - m\angle D \] \[ m\angle E = 180^\circ - 20^\circ - 60^\circ \] \[ m\angle E = 100^\circ \]
Now we have all the angles in triangle CDE:
- \( m\angle C = 20^\circ \)
- \( m\angle D = 60^\circ \)
- \( m\angle E = 100^\circ \)
In triangle PQR, the corresponding angles are:
- \( m\angle P = m\angle C = 20^\circ \)
- \( m\angle Q = m\angle D = 60^\circ \)
- \( m\angle R = m\angle E = 100^\circ \)
Thus, the measures of the angles in triangle PQR are:
- \( m\angle P = 20^\circ \)
- \( m\angle Q = 60^\circ \)
- \( m\angle R = 100^\circ \)