Asked by Raquel
Given triangleABC proportion to trianglePQR. If AB=4cm, BC=6cm, AC=9cm, and QR=4cm, find the perimeter of trianglePQR. What is the ratio of similitude?
Answers
Answered by
Steve
since the common sides have a constant ratio,
AB/PQ = BC/QR = CA/SP
4/PQ = 6/4 = 9/SP
the ratio is 6/4 = 3/2
so, the perimeters are also in that ratio, and
P(ABC) = 4+6+9 = 19
P(PQR) = 19 * 3/2
AB/PQ = BC/QR = CA/SP
4/PQ = 6/4 = 9/SP
the ratio is 6/4 = 3/2
so, the perimeters are also in that ratio, and
P(ABC) = 4+6+9 = 19
P(PQR) = 19 * 3/2
Answered by
Raquel
Two supplementary angles are in the ratio 5:7. Find the larger angle
Answered by
Arora
If you have a different question, you should post it as a new question, or a tutor may not see it.
Supplementary angles sum up to 180 degrees.
Taking the larger one as 7x, the smaller one is 5x (they are in a 5:7 ratio)
=> 5x + 7x = 180
=> 12x = 180
=> x = 15
Hence, the larger angle = 7x = 7(15) = 105
Supplementary angles sum up to 180 degrees.
Taking the larger one as 7x, the smaller one is 5x (they are in a 5:7 ratio)
=> 5x + 7x = 180
=> 12x = 180
=> x = 15
Hence, the larger angle = 7x = 7(15) = 105
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