To simplify the original expression \((3x−8)+(2x+5)−(4x−8)\), we can follow these steps:
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Distribute the negative sign: \[ (3x - 8) + (2x + 5) - 4x + 8 \]
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Combine like terms:
- Combine the \(x\) terms: \(3x + 2x - 4x = (3 + 2 - 4)x = x\)
- Combine the constant terms: \(-8 + 5 + 8 = -8 + 5 + 8 = -8 + 13 = 5\)
So the simplified expression is: \[ x + 5 \]
Now we look at the remaining expressions to find which ones are equivalent:
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\(3x−8+2x+5−4x−8\): This is the same as the original expression written out fully, so it simplifies to \(x + 5\).
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\(3x−8+2x+5−4x+8\): This has a \(+8\) instead of \(-8\) along with other terms. This leads to \[3x + 2x - 4x - 8 + 5 + 8 = (3 + 2 - 4)x + (-8 + 5 + 8) = x + 5\].
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\(x−5\): This simplifies to \(x - 5\), which is not equivalent to \(x + 5\).
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\(x−21\): This simplifies to \(x - 21\), which is not equivalent to \(x + 5\).
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\(10x−21\): This simplifies to \(10x - 21\), which is not equivalent to \(x + 5\).
Thus the three expressions that are equivalent to \(x + 5\) are:
- \(x + 5\)
- \(3x−8+2x+5−4x−8\)
- \(3x−8+2x+5−4x+8\)
These three answers are:
- \(x + 5\)
- \(3x−8+2x+5−4x−8\)
- \(3x−8+2x+5−4x+8\)