To find the area of the newspaper on the bottom of the cage, we need to first determine the dimensions of the bottom of the cage (which is shaped like a rectangle). We are given the volume of the rectangular prism (the cage) and its height.
The formula for the volume \( V \) of a rectangular prism is given by:
\[ V = \text{length} \times \text{width} \times \text{height} \]
We know:
- \( V = 7,280 \) cubic inches
- \( \text{height} = 26 \) inches
Let \( A \) represent the area of the bottom of the cage (length \(\times\) width). We can express the volume in terms of the area and height:
\[ 7,280 = A \times 26 \]
To find the area \( A \), we rearrange the equation:
\[ A = \frac{7,280}{26} \]
Now, we perform the division:
\[ A = 280 \text{ square inches} \]
Thus, the area of the newspaper on the bottom of the cage is
\[ \boxed{280} \] square inches.
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