Question

copper(II) sulfate pentahydrate molar mass

Answer 1

The molar mass of copper(II) sulfate pentahydrate (CuSO₄·5H₂O) can be calculated by adding the molar masses of its constituent elements.

1. **Copper (Cu)**: Approximately 63.55 g/mol
2. **Sulfur (S)**: Approximately 32.07 g/mol
3. **Oxygen (O)**: Approximately 16.00 g/mol
4. **Hydrogen (H)**: Approximately 1.01 g/mol

Now, let's calculate the molar mass step by step:

- Copper: 1 × 63.55 g/mol = 63.55 g/mol
- Sulfur: 1 × 32.07 g/mol = 32.07 g/mol
- Oxygen (from sulfate): 4 × 16.00 g/mol = 64.00 g/mol
- Water (5 molecules): 5 × (2 × 1.01 g/mol + 16.00 g/mol)
- For water: 5 × (2.02 g/mol + 16.00 g/mol) = 5 × 18.02 g/mol = 90.10 g/mol

Now, add these values together:

\[
\text{Molar Mass of CuSO₄·5H₂O} = 63.55 + 32.07 + 64.00 + 90.10 = 249.72 \, \text{g/mol}
\]

Thus, the molar mass of copper(II) sulfate pentahydrate is approximately **249.72 g/mol**.