Asked by Casey

Use the equation below and determine what volume of O2 at STP is needed to react with 1.5 moles of C2H4?

Balanced equation:

C2H4 + 3O2 --> 2CO2 + 2H20

So 1 mole of C2H4/3 mol O2 --> 1.5 mols/ 4.5 mols O2. So if its 1 mol equals 1 liter, than it should be 4.5 mols of O2 x 1 liter = 4.5 Liters O2.

Is this correct or am I missing something? I am trying to work out these equations but was not given an answer key to compare to.
Answered by DrBob222
4.5 moles O2 is correct for that part but why did you multiply by 1 L?
1 mole O2 at STP is 22.4 L so
4.5 moles x 22.4 L = ?? volume in liters for O2.
1 mole of any ideal gas occupies 22.4 L at STP.
Answered by Casey
I'm not sure why, I think I just had a brain spasm. Some reason I always think of converting mols to liters and I had it in my head that it was a 1:1 relationship but I think its 22.4L only when it applies to a gas?
Answered by DrBob222
! mole of an ideal gas occupies 22.4 L at STP. 1 mole of a solid or 1 mole of a liquid depend upon dimensions and or density.
Answered by alex
What volume of oxygen (O2) at STP is needed to react with 1.50 mol of C2H4?
Answered by alex
What volume of oxygen (O2) at STP is needed to react with 1.50 mol of C2H4?

Answered by alex
What is the percentage yield if 500 g of sulfur trioxide (SO3) reacts with 175 g water (H2O) to produce 575 g of sulfuric acid (H2SO4)?
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