Asked by Anonymous
Using the Nernst equation, determine the diluted concentration for both cells. Show your work.
Given that [Cu2+] and [Zn2+] are both 2M.
Note: I know that the nernst equation is
E= E*cell=(-0.0592 V/n)log Q
where Q in this case are [Sn2+]/[Cu2+] and [Zn2+]/[Sn2+].
I think that the E*cell = 0.30 for a)... but I am unsure of what the number for E is... I think the goal for part a) is to solve for [Sn2+] diluted and that in order to solve for it, the whole equation needs to be set equal to a number E that I am unsure of....
Are my thought processes correct?
a) Sn| Sn2+(diluted)||Cu2+|Cu
b) Zn| Zn2+ ||Sn2+(diluted)|Sn
Given that [Cu2+] and [Zn2+] are both 2M.
Note: I know that the nernst equation is
E= E*cell=(-0.0592 V/n)log Q
where Q in this case are [Sn2+]/[Cu2+] and [Zn2+]/[Sn2+].
I think that the E*cell = 0.30 for a)... but I am unsure of what the number for E is... I think the goal for part a) is to solve for [Sn2+] diluted and that in order to solve for it, the whole equation needs to be set equal to a number E that I am unsure of....
Are my thought processes correct?
a) Sn| Sn2+(diluted)||Cu2+|Cu
b) Zn| Zn2+ ||Sn2+(diluted)|Sn
Answers
Answered by
DrBob222
see above
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