Question

Find the distance, c, between (0, 0) and (–4, –3) on the coordinate plane. Round to the nearest tenth if necessary.

Answer 1

To find the distance \( c \) between the points \( (0, 0) \) and \( (-4, -3) \) on the coordinate plane, we can use the distance formula:

\[
c = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]

Here, we have:
- \( (x_1, y_1) = (0, 0) \)
- \( (x_2, y_2) = (-4, -3) \)

Substituting these values into the formula:

\[
c = \sqrt{((-4) - 0)^2 + ((-3) - 0)^2}
\]

This simplifies to:

\[
c = \sqrt{(-4)^2 + (-3)^2}
\]

Calculating the squares:

\[
c = \sqrt{16 + 9}
\]

Adding the values inside the square root:

\[
c = \sqrt{25}
\]

Finally, taking the square root:

\[
c = 5
\]

Thus, the distance between the points \( (0, 0) \) and \( (-4, -3) \) is \( \boxed{5} \).