Question

1C + 1CO2 = 2 CO
products: 8 CO
leftovers: 1 C, 0 CO2
what are the reactants?

Answer 1

To determine the reactants based on the provided reaction and leftovers, we need to analyze the stoichiometry of the reaction given:

1. **Balanced Chemical Equation**: The balanced equation is:
\[
1C + 1CO2 \rightarrow 2 CO
\]

2. **Products**: You have 8 CO as the product.

3. **Leftovers**: You have 1 carbon (C) and 0 carbon dioxide (CO2) left over.

### Finding the reactants:

From the balanced equation, we can see that:
- 1 mole of carbon (C) and 1 mole of carbon dioxide (CO2) produce 2 moles of carbon monoxide (CO).

Now, since you produced 8 moles of CO, we can relate this back to the number of reactants used:

- To produce 8 moles of CO, we would need:
\[
\text{For every 2 moles of CO produced, we need 1 mole of C and 1 mole of CO2}:
\]
\[
\text{So, for 8 moles of CO:}
\]
\[
\frac{8 \text{ CO}}{2 \text{ CO per reaction}} = 4 \text{ reactions needed}
\]

- Each reaction consumes 1 mole of C and 1 mole of CO2:
\[
\text{Total C used} = 4 \text{ moles}
\]
\[
\text{Total CO2 used} = 4 \text{ moles}
\]

### Analyzing Leftover Reactants:

From your information, you have leftover 1 mole of C and 0 moles of CO2:
- This means you started with 5 moles of C (4 used + 1 leftover).
- You used 4 moles of CO2, leaving 0 moles (i.e. you began with 4 moles of CO2).

### Summary of Initial Reactants:

To summarize, the reactants needed to produce the given products were:
- **5 moles of Carbon (C)** (4 used, 1 leftover)
- **4 moles of Carbon Dioxide (CO2)** (4 used, 0 leftover)

Thus, the initial amounts of the reactants were **5 C and 4 CO2**.