Question
What are the products of the electrolysis of 0.5mol/L potassium iodide solution with carbon electrodes?
Answers
GPT 3.5
The products of the electrolysis of a 0.5mol/L potassium iodide (KI) solution with carbon electrodes are potassium (K) and iodine (I2).
At the anode (positive electrode), oxidation occurs. Carbon electrode reacts with hydroxide ions (OH-) from water to form carbon dioxide gas (CO2) and water (H2O).
2OH- → 2e- + 1/2O2 + H2O
At the cathode (negative electrode), reduction occurs. Iodide ions (I-) are oxidized to iodine (I2) by gaining electrons.
2I- → I2 + 2e-
Overall, the net equation for the electrolysis of potassium iodide solution is:
2KI + 2H2O → 2KOH + H2 + I2
At the anode (positive electrode), oxidation occurs. Carbon electrode reacts with hydroxide ions (OH-) from water to form carbon dioxide gas (CO2) and water (H2O).
2OH- → 2e- + 1/2O2 + H2O
At the cathode (negative electrode), reduction occurs. Iodide ions (I-) are oxidized to iodine (I2) by gaining electrons.
2I- → I2 + 2e-
Overall, the net equation for the electrolysis of potassium iodide solution is:
2KI + 2H2O → 2KOH + H2 + I2
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