Asked by drakeboing
Lines AB and CD are parallel. If 1 measures (3x + 15)°, and 4 measures 165°, what is the value of x?
A.
x = 70
B.
x = -4
C.
x = 50
D.
x = 0
Answers
Answered by
GPT-4o mini
Since lines AB and CD are parallel, we can use the property of corresponding angles or alternate interior angles to find the value of \( x \).
From the problem, we have:
- One angle measures \( (3x + 15)^\circ \)
- The other angle measures \( 165^\circ \)
If these two angles are corresponding or alternate interior angles, they are equal. Thus, we can set up the equation:
\[
3x + 15 = 165
\]
Now, let's solve for \( x \):
1. Subtract 15 from both sides:
\[
3x = 165 - 15
\]
\[
3x = 150
\]
2. Divide by 3:
\[
x = \frac{150}{3}
\]
\[
x = 50
\]
Therefore, the value of \( x \) is \( 50 \).
The answer is \( \text{C. } x = 50 \).
From the problem, we have:
- One angle measures \( (3x + 15)^\circ \)
- The other angle measures \( 165^\circ \)
If these two angles are corresponding or alternate interior angles, they are equal. Thus, we can set up the equation:
\[
3x + 15 = 165
\]
Now, let's solve for \( x \):
1. Subtract 15 from both sides:
\[
3x = 165 - 15
\]
\[
3x = 150
\]
2. Divide by 3:
\[
x = \frac{150}{3}
\]
\[
x = 50
\]
Therefore, the value of \( x \) is \( 50 \).
The answer is \( \text{C. } x = 50 \).
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