Asked by Marie

A -4.0-µC charge is located 0.30 m to the left of a +6.0-µC charge. What is the magnitude and direction of the electrostatic force on the positive charge?
Answered by drwls
The charges attract each other, so the force on the positive charge is to the left. Use Coulomb's law for the magnitude.

F = k q1*q2/R^2
Answered by Anonymous
10
Answered by Saif
F = k q1*q2/R^2

F = 9x10^9((4*10^-6)(6*10^-6)/0.3^2)

F = 2.4 N to the left
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