The charges attract each other, so the force on the positive charge is to the left. Use Coulomb's law for the magnitude.
F = k q1*q2/R^2
F = k q1*q2/R^2
F = 9x10^9((4*10^-6)(6*10^-6)/0.3^2)
F = 2.4 N to the left
First of all, we need to use Coulomb's Law, which states that the magnitude of the electrostatic force between two charges is given by:
F = k * (|q1| * |q2|) / r^2
Here, k is the electrostatic constant, |q1| and |q2| are the magnitudes of the charges, and r is the distance between them.
Plugging in the values:
k = 8.99 * 10^9 N·m^2/C^2
|q1| = 4.0 * 10^-6 C
|q2| = 6.0 * 10^-6 C
r = 0.30 m
Calculating:
F = (8.99 * 10^9 N·m^2/C^2) * (4.0 * 10^-6 C * 6.0 * 10^-6 C) / (0.30 m)^2
After crunching the numbers, the result is approximately 2.39 N.
Now, as for the direction of the force, since the charges have opposite signs, they will attract each other. The force will be directed from the negative charge (left) towards the positive charge (right).
So, to sum it up, the magnitude of the electrostatic force is approximately 2.39 N, and its direction is from left to right. These charges are definitely not clowning around when it comes to their attraction!
F = k * (|q1| * |q2|) / r^2
where F is the electrostatic force, k is the electrostatic constant (8.99 x 10^9 N m^2/C^2), |q1| and |q2| are the magnitudes of the charges, and r is the distance between the charges.
In this case, the magnitudes of the charges are |q1| = 4.0 x 10^-6 C and |q2| = 6.0 x 10^-6 C, and the distance between them is r = 0.30 m.
Plugging these values into the formula, we have:
F = (8.99 x 10^9 N m^2/C^2) * ((4.0 x 10^-6 C) * (6.0 x 10^-6 C)) / (0.30 m)^2
Simplifying, we get:
F = (8.99 x 10^9 N m^2/C^2) * (24 x 10^-12 C^2) / (0.09 m^2)
F = (8.99 x 24 x 10^-3 N) / (0.09 m^2)
F = 215.24 x 10^-3 N
Therefore, the magnitude of the electrostatic force on the positive charge is 215.24 x 10^-3 N.
To determine the direction, we need to consider the charges' polarities. The positive charge will experience a force towards the negative charge, in the direction away from the negative charge. Therefore, the direction of the electrostatic force on the positive charge is to the left.