Question

A -4.0-µC charge is located 0.30 m to the left of a +6.0-µC charge. What is the magnitude and direction of the electrostatic force on the positive charge?

Answers

drwls
The charges attract each other, so the force on the positive charge is to the left. Use Coulomb's law for the magnitude.

F = k q1*q2/R^2
Anonymous
10
Saif
F = k q1*q2/R^2

F = 9x10^9((4*10^-6)(6*10^-6)/0.3^2)

F = 2.4 N to the left

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