Question

writing linear eqautions from standard form to slope-intercept form
x+8y=0

Answer 1

To convert the equation from standard form (Ax + By = C) to slope-intercept form (y = mx + b), you need to solve for \( y \).

Given the equation:

\[ x + 8y = 0 \]

Follow these steps:

1. **Isolate the \( y \) term**:

Subtract \( x \) from both sides:
\[
8y = -x
\]

2. **Solve for \( y \)**:

Divide both sides by 8:
\[
y = -\frac{1}{8}x
\]

Now, the equation is in slope-intercept form \( y = mx + b \), where:
- The slope \( m = -\frac{1}{8} \)
- The y-intercept \( b = 0 \)

So the final slope-intercept form of the equation is:

\[
y = -\frac{1}{8}x
\]