Ask a New Question

Question

A buffer prepared by mixing equal amounts of the salts Na2HPo4 and NaH2PO4 to give a total phosphate concentration of 0.1M. What is the concentration of Na ions?

I believe it is 0.3M but am having trouble understanding why when I write out the dissociation of the Na2HPo4 and NaH2PO4. Thanks
15 years ago

Answers

Related Questions

A buffer is prepared by mixing 110. mL of 0.442 M HCl and 0.545 L of 0.400 M sodium acetate. How man... A buffer is prepared by mixing 205 mL of .452 M HCl and .500 L of .400 M sodium acetate. (Ka =1.80... A buffer is prepared by mixing 205 mL of .452 M HCl and .500 L of .400 M sodium acetate. Ka =1.80 x... A buffer is prepared by mixing 45.0 mL of 0.15 M NaF to 35.0 mL of 0.10 M HF (Ka = 6.8x10^-4) Calcul... a buffer prepared by mixing equal moles of an acid having Ka=4.5x10^-4 and a salt of its conjugate b... 'A buffer is prepared by mixing a 100.omL of a 0.100 M NH3 solution with a 0.200M solution of NH4CL... A buffer is prepared by mixing 20 mL of .10 HOCl with 20 mL of .05 M NaOCl, and measure the pH to be... A buffer was prepared by mixing 0.1 M ch3cooh with 0.1M ch3cooNa in the ratio 8:2. Calculate ph afte... A buffer was prepared by mixing 1.00 mol of ammonia 𝑁𝐻3 πΎπ‘Ž = 5.8 Γ— 10βˆ’10 and 1.00 mol of ammonium c... A buffer is prepared by mixing 200ml of 0.2M salt solution and 400ml of 0.2M acid solution. what's...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use