Asked by Anonymous
A buffer is prepared by mixing 200ml of 0.2M salt solution and 400ml of 0.2M acid solution. what's the concentration of the resulting buffer
Answers
Answered by
DrBob222
millimoles salt = mL x M = 200 x 0.2 M = 40
millimoles acid = 400 x 0.2 M = 80
millimoles total = 120
volume total = 600 mL
M = millimoles/ L = 120/600 = 0.2 M
millimoles acid = 400 x 0.2 M = 80
millimoles total = 120
volume total = 600 mL
M = millimoles/ L = 120/600 = 0.2 M
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