Asked by ac
A track star in the long jump goes into the jump at 12 m/s and launches herself at 20 degrees above the horizontal. How long is she in the air before returning to Earth? (g= 9.81 m/s squared)
I tried using some formulas but I'm using all of the wrong formulas for this question. I can work this out if someone can give me the correct formula to use. :)
Thanks!
I tried using some formulas but I'm using all of the wrong formulas for this question. I can work this out if someone can give me the correct formula to use. :)
Thanks!
Answers
Answered by
bobpursley
You know the intial height, and the final height. You know the initial velocity.
hfinal=hinitial + v*sin20*t -1/2 g t^2
solve for t.
hfinal=hinitial + v*sin20*t -1/2 g t^2
solve for t.
Answered by
ac
Thanks! ^^
Answered by
j
200
Answered by
Deanna
0.83 seconds
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.