Asked by seth
                How much limestone (CaCO3) in kilograms would be 
required to completely neutralize a lake with a volume of 5.2 x 10^9L . The lake contains 5.0 x 10^-3 moles of H2SO4 per liter?
 
            
            
        required to completely neutralize a lake with a volume of 5.2 x 10^9L . The lake contains 5.0 x 10^-3 moles of H2SO4 per liter?
Answers
                    Answered by
            bobpursley
            
    Multiply the volume of the lake by the concentration, that will give you the moles of sulfuric acid.  It will take a similar number of moles of limestone.
    
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