Question

The Vapor pressures of pure propyl alcohol and isopropyl alcohol are 21.0 mmHg and 45.2 mmHg, respectively, at 25 (degrees)C. Calculate the partial pressure of isopropyl alcohol above a solution in which the mole fraction of propyl alchol is 0.250.
P<sub>soln</sub> = X<sub>ip</sub>*P<sup>o</sup><sub>ip</sub>

Xpropyl = 0.250; therefore, Xipropyl = 0.750
Plug into the above.
Check my thinking.

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