Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
A cube box is 20x20x20 cm what is the surface area of the largest size sphere than can fit in this box leave your answer in ter...Asked by Lee
a cube box is 20 cm x 20 cm x 30 cm what is the surface area of the largest size sphere that can fit in this box? leave your answer in terms of pi
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine the largest sphere that can fit inside a rectangular box, we need to find the diameter of the sphere, which will be equal to the smallest dimension of the box.
The dimensions of the box are:
- Length: 30 cm
- Width: 20 cm
- Height: 20 cm
The smallest dimension here is 20 cm. Therefore, the diameter of the largest sphere that can fit in the box is 20 cm.
The radius \( r \) of the sphere is half of the diameter:
\[
r = \frac{d}{2} = \frac{20 \, \text{cm}}{2} = 10 \, \text{cm}
\]
The formula for the surface area \( A \) of a sphere is given by:
\[
A = 4\pi r^2
\]
Substituting the radius into the formula:
\[
A = 4\pi (10 \, \text{cm})^2
\]
\[
A = 4\pi (100 \, \text{cm}^2)
\]
\[
A = 400\pi \, \text{cm}^2
\]
Thus, the surface area of the largest sphere that can fit in the box is
\[
\boxed{400\pi} \, \text{cm}^2
\]
The dimensions of the box are:
- Length: 30 cm
- Width: 20 cm
- Height: 20 cm
The smallest dimension here is 20 cm. Therefore, the diameter of the largest sphere that can fit in the box is 20 cm.
The radius \( r \) of the sphere is half of the diameter:
\[
r = \frac{d}{2} = \frac{20 \, \text{cm}}{2} = 10 \, \text{cm}
\]
The formula for the surface area \( A \) of a sphere is given by:
\[
A = 4\pi r^2
\]
Substituting the radius into the formula:
\[
A = 4\pi (10 \, \text{cm})^2
\]
\[
A = 4\pi (100 \, \text{cm}^2)
\]
\[
A = 400\pi \, \text{cm}^2
\]
Thus, the surface area of the largest sphere that can fit in the box is
\[
\boxed{400\pi} \, \text{cm}^2
\]
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.