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Consider the quadratic function that represents the inverse of the graphed square root function. What would be the vertex of the related quadratic function? (1 point) ((),())
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GPT-4o mini
The graph of the square root function is typically \( f(x) = \sqrt{x} \), which has a vertex at the origin point (0,0).
To find the inverse of this function, we start with \( y = \sqrt{x} \) and solve for \( x \):
1. Square both sides: \( y^2 = x \).
2. Rearranging gives us the inverse function: \( x = y^2 \) or \( f^{-1}(x) = x^2 \).
The graph of this inverse function, \( f^{-1}(x) = x^2 \), is a quadratic function.
For the quadratic function \( f(x) = x^2 \), the vertex is at the point (0,0).
Thus, the vertex of the related quadratic function is:
\[
(0, 0)
\]
To find the inverse of this function, we start with \( y = \sqrt{x} \) and solve for \( x \):
1. Square both sides: \( y^2 = x \).
2. Rearranging gives us the inverse function: \( x = y^2 \) or \( f^{-1}(x) = x^2 \).
The graph of this inverse function, \( f^{-1}(x) = x^2 \), is a quadratic function.
For the quadratic function \( f(x) = x^2 \), the vertex is at the point (0,0).
Thus, the vertex of the related quadratic function is:
\[
(0, 0)
\]
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