Question

or
Solve using substitution.

–10x + 3y = 16
y = –8

(
,
)

Answer 1

To solve the system of equations using substitution, we have:

1. \(-10x + 3y = 16\)
2. \(y = -8\)

Since the second equation already gives us the value of \(y\), we can substitute \(y = -8\) into the first equation.

Substituting \(y\) into the first equation:

\[
-10x + 3(-8) = 16
\]

Calculating \(3(-8)\):

\[
-10x - 24 = 16
\]

Next, we isolate the term with \(x\):

\[
-10x = 16 + 24
\]

\[
-10x = 40
\]

Now, divide by -10:

\[
x = \frac{40}{-10} = -4
\]

Now we have both \(x\) and \(y\):

\[
x = -4, \quad y = -8
\]

Thus, the solution to the system of equations is:

\[
\boxed{(-4, -8)}
\]