Asked by Jim
A 0.90g sample of liquid water was introduced into an evacuated 2.00 L flask, which was then sealed and heated to 37 (degree)C. What percentage, by mass, of the water remained as liquid? [Vapor pressure of water at 37 (degree)C=48.2 torr]
Answers
Answered by
bobpursley
mass of water vapor:
n=PV/RT caculate n using P=vapor pressure.
change moles (n) to grams.
subtract that from the original mass of water, then you have it.
n=PV/RT caculate n using P=vapor pressure.
change moles (n) to grams.
subtract that from the original mass of water, then you have it.
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