Asked by JAS
Calcium nitrate will react with ammonium chloride at slightly elevated temperatures, as represented in the equation
Ca(NO3)2(s) + 2NH4Cl(s) ---> 2N2O(g) + CaCl2(s) + 4H2O(g)
What is the maximum volume of N2O at STP that could be produced using a 6.80-mol sample of each reactant?
Answer
0.007 L
1856 L
22.4 L
305 L
152 L
Ca(NO3)2(s) + 2NH4Cl(s) ---> 2N2O(g) + CaCl2(s) + 4H2O(g)
What is the maximum volume of N2O at STP that could be produced using a 6.80-mol sample of each reactant?
Answer
0.007 L
1856 L
22.4 L
305 L
152 L
Answers
Answered by
bobpursley
WEll, 1 mole of Calcium nitrate will yield 2 moles of N2O. Each mole of gas occupies 22.4 liters.
So 6.8*2*22.4=
So 6.8*2*22.4=
Answered by
Sam
22.4
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