Question
Determine whether the function f, of, x, equals, x, squared, plus, x, to the power 4 , plus, 2f(x)=x
2
+x
4
+2 is even, odd or neither.
Answer
Attempt 1 out of 2
Multiple Choice Answers
odd
neither
even
2
+x
4
+2 is even, odd or neither.
Answer
Attempt 1 out of 2
Multiple Choice Answers
odd
neither
even
Answers
Answered by
GPT-4o mini
To determine whether the function \( f(x) = x^2 + x^4 + 2 \) is even, odd, or neither, we follow these definitions:
- A function is **even** if \( f(-x) = f(x) \) for all \( x \).
- A function is **odd** if \( f(-x) = -f(x) \) for all \( x \).
Let's calculate \( f(-x) \):
\[
f(-x) = (-x)^2 + (-x)^4 + 2
\]
Calculating each term:
\[
(-x)^2 = x^2
\]
\[
(-x)^4 = x^4
\]
Putting it together, we get:
\[
f(-x) = x^2 + x^4 + 2
\]
Now, compare \( f(-x) \) with \( f(x) \):
\[
f(x) = x^2 + x^4 + 2
\]
Since \( f(-x) = f(x) \), the function satisfies the condition for being even.
Thus, the answer is:
**even**
- A function is **even** if \( f(-x) = f(x) \) for all \( x \).
- A function is **odd** if \( f(-x) = -f(x) \) for all \( x \).
Let's calculate \( f(-x) \):
\[
f(-x) = (-x)^2 + (-x)^4 + 2
\]
Calculating each term:
\[
(-x)^2 = x^2
\]
\[
(-x)^4 = x^4
\]
Putting it together, we get:
\[
f(-x) = x^2 + x^4 + 2
\]
Now, compare \( f(-x) \) with \( f(x) \):
\[
f(x) = x^2 + x^4 + 2
\]
Since \( f(-x) = f(x) \), the function satisfies the condition for being even.
Thus, the answer is:
**even**
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