Question

Determine whether the function of f(x)=[[x+1]] is odd, even, or neither.

I figured since it's a step function it automatically couldn't have symmetry and therefore is neither.
and doing the whole f(-x) thing:
f(-x)=[[-x+1]]

which is not equal to f(x) or -f(x).
so the answer would be neither, right?

Answer 1

I am not certain of your symbols

If you mean f(x)=absolute(x+1) then it is even, with a line of symettry at x=-1

Answer 2

it's a greatest integer function (AKA step function)
not absolute value.