Asked by Jennifer
Determine whether the function of f(x)=[[x+1]] is odd, even, or neither.
I figured since it's a step function it automatically couldn't have symmetry and therefore is neither.
and doing the whole f(-x) thing:
f(-x)=[[-x+1]]
which is not equal to f(x) or -f(x).
so the answer would be neither, right?
I figured since it's a step function it automatically couldn't have symmetry and therefore is neither.
and doing the whole f(-x) thing:
f(-x)=[[-x+1]]
which is not equal to f(x) or -f(x).
so the answer would be neither, right?
Answers
Answered by
bobpursley
I am not certain of your symbols
If you mean f(x)=absolute(x+1) then it is even, with a line of symettry at x=-1
If you mean f(x)=absolute(x+1) then it is even, with a line of symettry at x=-1
Answered by
Jennifer
it's a greatest integer function (AKA step function)
not absolute value.
not absolute value.
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