Question

What is the width of a rectangle with a length of 6/7 feet and an area of 5 square feet?

Answer 1

To find the width of a rectangle given its length and area, you can use the formula for the area of a rectangle:

\[
\text{Area} = \text{Length} \times \text{Width}
\]

In this case, you are given:

- Length = \( \frac{6}{7} \) feet
- Area = 5 square feet

Let \( W \) represent the width of the rectangle. We can rearrange the area formula to solve for the width:

\[
W = \frac{\text{Area}}{\text{Length}}
\]

Substituting the values we have:

\[
W = \frac{5 \text{ square feet}}{\frac{6}{7} \text{ feet}}
\]

To divide by a fraction, you multiply by its reciprocal:

\[
W = 5 \text{ square feet} \times \frac{7}{6} \text{ feet}^{-1}
\]

Calculating this gives:

\[
W = \frac{5 \times 7}{6} = \frac{35}{6}
\]

Thus,

\[
W = \frac{35}{6} \text{ feet}
\]

Converting \( \frac{35}{6} \) to a mixed number, we find that:

\[
\frac{35}{6} = 5 \frac{5}{6}
\]

Therefore, the width of the rectangle is

\[
\frac{35}{6} \text{ feet} \quad \text{or} \quad 5 \frac{5}{6} \text{ feet}.
\]