Question
A square has an area of S^2 and a regular hexagon has a perimeter of T. If p is the perimeter of the square and h is a side of the hexagon, then find h+p in terms of S and T.
Answers
Henry
SQUARE: A=S^2=S.S, Perimeter=P=4S.
REGULAR HEXAGON: Perimeter=T=6h,h=T/6.
h+P=T/6+4S.
REGULAR HEXAGON: Perimeter=T=6h,h=T/6.
h+P=T/6+4S.
Lucy
square A=S^2, P=p (side of the square must be S, p=4(S))
Regular Hexagon P=T and side=h (side is total perimeter divided by the sides of the hexagon (6))
therefore, h+p in terms of S and T.
(P/6)+ 4S
Regular Hexagon P=T and side=h (side is total perimeter divided by the sides of the hexagon (6))
therefore, h+p in terms of S and T.
(P/6)+ 4S