Asked by anonymous
I'm reviewing for my exams, and I was sure that I was comfortable with solving trigonometric identities, but now that I'm looking at ones on my review, I'm not so sure. Could someone please show me, step by step, how to answer one?
[cos^2theta] / [1 +2sintheta -2sin^2theta]
is equal to
[1 +sintheta] / [1 +3sintheta]
Thanks in advance :)
[cos^2theta] / [1 +2sintheta -2sin^2theta]
is equal to
[1 +sintheta] / [1 +3sintheta]
Thanks in advance :)
Answers
Answered by
Damon
I think you have a typo - see my 3 below
-[1-s^2] / [3s^2 -2s -1]
(not 2s^2-2s-1)
[(s-1)(s+1)] / [ (s-1) (3s+1) ]
-[1-s^2] / [3s^2 -2s -1]
(not 2s^2-2s-1)
[(s-1)(s+1)] / [ (s-1) (3s+1) ]
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