Question

how much chocolate is in a spherical chocolate truffle with a radius of 12, use 3.14 for pi and round the nearest hundredth

Answer 1

To find the amount of chocolate in a spherical chocolate truffle, we need to calculate the volume of the sphere. The formula for the volume \( V \) of a sphere is given by:

\[
V = \frac{4}{3} \pi r^3
\]

where \( r \) is the radius of the sphere.

Given that the radius \( r \) is 12, and using \( \pi \) as 3.14, we can substitute these values into the formula:

\[
V = \frac{4}{3} \times 3.14 \times (12)^3
\]

First, we calculate \( (12)^3 \):

\[
12^3 = 12 \times 12 \times 12 = 1728
\]

Next, substitute this value back into the volume formula:

\[
V = \frac{4}{3} \times 3.14 \times 1728
\]

Now calculate \( \frac{4}{3} \times 3.14 \):

\[
\frac{4}{3} \times 3.14 \approx 4.18667
\]

Now multiply this by 1728:

\[
V \approx 4.18667 \times 1728 \approx 7227.99936
\]

Rounding to the nearest hundredth, the volume (and thus the amount of chocolate in the spherical truffle) is:

\[
V \approx 7228.00 \, \text{cubic units}
\]

So, there are approximately **7228.00 cubic units** of chocolate in the truffle.